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Re: Intersection
yeah this one can be done pretty quickly if you think about it right
dragonfinity has the right idea... you don't care what the points actually are and you don't want to bother taking the time to draw the graph
since the functions are continuous you compare the values on different intervals, like between 1 and 2 for example, f(1)=1^12 = 1 and g(1)=2^1 = 2 so f<g, but f(2) = 2^12 (whatever this ends up being) > g(2) = 2^2 = 4 so there must be a point of intersection between x=1 and 2. etc. I think dragonfinity explained it more thoroughly
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