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samy_dg · 2005 June 13th, 05:09 AM

1. In a 100m race, A can beat B by 25 m and B can beat C by 4m.In the same race, A can beat C by:
Let,
Speed of A=a
Speed of B=b
Speed of C=c
Then (100/a)Xb=100-25=75...........(i)
(100/b)Xc=100-4=96............(ii)
(i)X(ii)....(10000/a)Xc=75X96
So, (100/a)Xc=75X96/100=72=100-28.
So, answer=28m .......(C)

2005 June 13th, 05:09 AM	#2 (permalink)
samy_dg Somebody Stop Me !! Join Date: May 2005 Location: Waterloo, ON, Canada Posts: 1,220	Re: Race problems from practice tests 1. In a 100m race, A can beat B by 25 m and B can beat C by 4m.In the same race, A can beat C by: Let, Speed of A=a Speed of B=b Speed of C=c Then (100/a)Xb=100-25=75...........(i) (100/b)Xc=100-4=96............(ii) (i)X(ii)....(10000/a)Xc=75X96 So, (100/a)Xc=75X96/100=72=100-28. So, answer=28m .......(C) _ _ _ _ SIG _ _ _ _ Nothing's impossible. ______________________________________