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Let the 3 Asians b considered as one person/seat
Similarly let 2 Europeans b considered as one person/seat
So now we have 3 people (1 Asian,1 European and 1 American) to arrange on 3 seats.
=3!=6
But the 3 Asians and 2 Europeans can sit in 3! and 2! different ways
So for each 3! arrangements,there r 6 possiblities for Asains and 2 possiblities for Europeans.
i.e. 3!* 3!* 2!=6*6*2=72
Let me know the correct answer...
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