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some useful formula...
if the number of men are 2, a,b speeds with a>b
time taken for them to meet first = L/(a-b) [both runs in same direction]
time taken for them to meet first = L/(a+b) [both runs in opposite direction]
time taken for them to meet first at starting point is
LCM of (L/a , L/b) for both same and opposite direction.
If the number of men are 3 ,a,b,c are speeds..a>b>c
Time taken for them to meet first time is
LCM of [L/(a-b),L/(b-c)]
Time taken for them to meet first time at the starting point is
LCM of [L/a,L/b,L/c]
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