Hi! That is really buffling question for me as well, but I cannot understand another variant:
Quote:
Originally Posted by lmtuan
Since f is a real-valued function defined and continuous on the set of real numbers R, f is continuous on [0,1]. Thus, f([0.1]) is bounded.
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*by the way the question was about (0,1) not [0,1].
WHY? If f=tan(Pi/2*(x-0.5)) so in that case we have (0,1)->(-inf, +inf) and it is not bounded? Where am I wrong?
