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Old 2007 December 13th, 12:56 AM   #9 (permalink)
lmtuan
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Join Date: Oct 2004
Location: Vietnam
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Quote:
Originally Posted by lime View Post
Hi! That is really buffling question for me as well, but I cannot understand another variant:

*by the way the question was about (0,1) not [0,1].

WHY? If f=tan(Pi/2*(x-0.5)) so in that case we have (0,1)->(-inf, +inf) and it is not bounded? Where am I wrong?
Your function is not defined at all real numbers.
I used [0,1] since (0,1) is a subset of [0,1]. ([0,1] is very nice, it is closed, bounded, compact, connected.) Since f is continuous in R, f also is continuous in [0,1].....
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