[putneyswope]

Originally Posted by siliconfish

Crowan throws 3 dice and records the product of the numbers appearing at the top of each die as a result of the attempt. What is the probability that the result of any attempt is an odd integer divisible by 25?

My problem with the above question is whether we need to consider each set of result as a distinct possibility such as 5 5 3 and 5 3 5 . If so can you please explain the reasoning.

Thanks in advance.

Think about a place holder of three spots for each dice:

_ _ _

155 (you could throw a 1 first, then a 5, then a 5)
515 (you could throw a 5 first, then a 1, then a 5)
551 ...
355 ...
535
553
555

So probability is 7/6^3.

but i'm no math guru!