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area of the given square is 100
==> l^2 = 100 where l is the length on one side
given that one vertice is (0,0) lets assume the other vertice is (m,n)
solving for 1st quadrant the m & n are positive we can represent length of l
==> (0-m)^2 + (0-n)^2 = 100=10^2
==> 6^2 + 8^2 = 10^2
so one vertice is (6,8) similarly other can be (8,6)
also one more is obviously (10,0)
so 3 vertice is 1st quadrant
==> for all 4 quardrant we can have 4*3 = 12 squares.
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