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suwarnapatel · 07-11-2008, 01:02 AM

Simpler method:

f(m)=9f(v)
Try 9 against 2,3 and 5

3^2 = 9

So we know tens digit is greater by 2 in m than v.

difference = 10 (tens digit) * 2 = 20.

07-11-2008, 01:02 AM	#4 (permalink)
suwarnapatel Within my grasp! Join Date: Jul 2008 Posts: 134	Simpler method: f(m)=9f(v) Try 9 against 2,3 and 5 3^2 = 9 So we know tens digit is greater by 2 in m than v. difference = 10 (tens digit) * 2 = 20.