TestMagic Forums - View Single Post - (2m - n + m) / (n-m)?

btit · 07-21-2008, 04:17 PM

Strange.. I am getting D.

Stmt 1: As explained by everyone.
Stmt 2: 2m-n+m / n-m = 2m-(n-m) / n-m = (2m/n-m) -1 =0

So, 2m/n-m = 1
So, 2m/6 = 1 i.e. 2m = 6.. so, m = 3 and n=9. Suff

Anything wrong??

07-21-2008, 04:17 PM	#10 (permalink)
btit Within my grasp! Join Date: May 2008 Posts: 104	Strange.. I am getting D. Stmt 1: As explained by everyone. Stmt 2: 2m-n+m / n-m = 2m-(n-m) / n-m = (2m/n-m) -1 =0 So, 2m/n-m = 1 So, 2m/6 = 1 i.e. 2m = 6.. so, m = 3 and n=9. Suff Anything wrong??