Quote:
Originally Posted by chestnut.cc
Q.how many 5 digit nos. can be formed using the digits 0 2 3 4 5 when repetition is allowed such that the number is divisible by 2 or 5 or both?
If the question means 2 and 5 or both... 4*5*5*5*2 + 4*5*5*5*1... 1500
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Sorry for the miscalculation for this q. But can someone explain why #1 shouldn't be 4*5*5*5*4 if it's asking for "divisible by 2 or 5 or both?"
Can someone remind me the shortcut to simplify 3N^2 - 11n - 4 to get n= 4 or -1/3? I know this is highschool math...but it's been a few years and i really can't remember.