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prithibi · 07-22-2008, 07:00 AM

oh! sure,
3n^2-11n-4=0
3n^2-12n+n-4=0
3n(n-4)+1(n-4)=0
(n-4)(3n+1)=0
either n-4=0 or 3n+1=0
i.e. n= 4 or n= -1/3

07-22-2008, 07:00 AM	#13 (permalink)
prithibi Eager! Join Date: Jul 2008 Posts: 89	oh! sure, 3n^2-11n-4=0 3n^2-12n+n-4=0 3n(n-4)+1(n-4)=0 (n-4)(3n+1)=0 either n-4=0 or 3n+1=0 i.e. n= 4 or n= -1/3