TestMagic Forums - View Single Post - How to solve this kind of standard deviation sums???

sanjeev_sharma · 07-23-2008, 12:44 PM

Since this is a normal distribution of mean, the % of population <= 68 + ((100-68)/2) = 68 + 32/2 = 68 + 16 = 84%

07-23-2008, 12:44 PM	#3 (permalink)
sanjeev_sharma Within my grasp! Join Date: May 2008 Posts: 242	Since this is a normal distribution of mean, the % of population <= 68 + ((100-68)/2) = 68 + 32/2 = 68 + 16 = 84%