Thread: How to solve this kind of standard deviation sums???
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Old 07-23-2008, 01:24 PM   #4 (permalink)
GmatG
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Quote:
Originally Posted by sanjeev_sharma View Post
Since this is a normal distribution of mean, the % of population <= 68 + ((100-68)/2) = 68 + 32/2 = 68 + 16 = 84%
Agree to Sanjeev Sharma IMO 84%
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