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Old 07-24-2008, 12:43 PM   #8 (permalink)
sandipank
Eager!
 
Join Date: Jul 2008
Posts: 77
sandipank just joined TestMagic.
Quote:
Originally Posted by giddy View Post
Thanks, Goldust. The only way I was solving it that was making sense to me was that I multiplied 6 and 8 and added 5. But I left out 3 so that won't work. Your explanation was greatly appreciated. Thank you.
You can solve this problem in this way also...
D:R=5:6 and R:E=8:3
now when taking composite ratio(I forgot the exact term) for D:R:E=5*8:6*8:3*6=40:48:18=20:24:9(Make the common term i.e. Ruby as 48 by taking LCM). so min no. of jewels =53
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