Quote:
Originally Posted by lime
Consider group Z15 under addition. Then element x=5 satisfies given conditions. Indeed:
5^3=3*5=15=0
5^5=5*5=25=10
5^9=9*5=45=0
Then
x^13=65=5
Element 5 generates subgroup of order 3.
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why are u taking products of power and the element? it is supposed to be x^3= 5^3 = 125 right? why are u taking the product 5*3?? Thanks a lot for your time!
