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eravi11 · 2009 June 20th, 11:38 AM

Statement 1 yields: Either b > a or b < -a
Now a-b/a+b <1 can be rewritten as [1-(b/a)]/[1+(b/a)]<1 Putting values it can be proven that statement 1 is insuffiicient.

Using Statement 2 we can prove that a-b/a+b <1 or a-b/a+b>1 Hence INSUFFICIENT

Combining 1 and 2 we have b<-a and a-b>1 INSUFFICIENT.

I think it is E..What is OA?

2009 June 20th, 11:38 AM	#2 (permalink)
eravi11 So far So bad! Join Date: Feb 2009 Posts: 631	Statement 1 yields: Either b > a or b < -a Now a-b/a+b <1 can be rewritten as [1-(b/a)]/[1+(b/a)]<1 Putting values it can be proven that statement 1 is insuffiicient. Using Statement 2 we can prove that a-b/a+b <1 or a-b/a+b>1 Hence INSUFFICIENT Combining 1 and 2 we have b<-a and a-b>1 INSUFFICIENT. I think it is E..What is OA?