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spacepure · 2009 June 23rd, 10:29 AM

(a-b)/(b+a) <1
<=> (a-b)/(b+a) -1<0
<=> (-2b)/(a+b)<0
<=> b>0

Thus, it has nothing to do with 1 and 2

2009 June 23rd, 10:29 AM	#3 (permalink)
spacepure Confident and Positive Join Date: Mar 2009 Posts: 59	(a-b)/(b+a) <1 <=> (a-b)/(b+a) -1<0 <=> (-2b)/(a+b)<0 <=> b>0 Thus, it has nothing to do with 1 and 2