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saravanants · 2009 June 27th, 11:12 PM

1) Answer E.
2) 1 => a+b = 1 and 2 => ab = -6. Combining both can answer the question C.
3) This is a combination problem and not a permutation problem as we cannot select the same group again but in reversed order

For example women#1,women#2,women#3 if formed as one group, then we cannot count another group as women#3, women#2, women#1. So right answer should be 5c3*7C1 = 10*7 = 70.

2009 June 27th, 11:12 PM	#14 (permalink)
saravanants Eager! Join Date: Jun 2009 Posts: 54	1) Answer E. 2) 1 => a+b = 1 and 2 => ab = -6. Combining both can answer the question C. 3) This is a combination problem and not a permutation problem as we cannot select the same group again but in reversed order For example women#1,women#2,women#3 if formed as one group, then we cannot count another group as women#3, women#2, women#1. So right answer should be 5c37C1 = 107 = 70.