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audia8 · 2009 July 2nd, 06:49 PM

I go with A. The question I have is I get the 15 unique factors for X from 1)

x=a2b3=>4C1+4C2+4C3+4C4=15. Correct me, if I'm wrong. Thanks.

2009 July 2nd, 06:49 PM	#3 (permalink)
audia8 I JUST got here. Join Date: Jun 2009 Posts: 6	I go with A. The question I have is I get the 15 unique factors for X from 1) x=a2b3=>4C1+4C2+4C3+4C4=15. Correct me, if I'm wrong. Thanks.