Quote:
Originally Posted by dissa
hmm.. b/n between? I didn't get it. 
My answer is here,
h(n) = 2 x 4 x .....n
h(100) = 2 x 4 x ...100
h(100) + 1 = (2 x 4 x ...100 + 1) = 2^50 (1 x 2 x...50) +1
if we divide this any number below 50;
1 would be the remainder. So that the smallest prime factor would be greater than 50.
answer (E) |
Great ... this question stumped me and your's is a beautiful and simple approach that we can reuse! Thanks a lot, dissa!
The other two questions are relatively much simpler ...
2. (E) ... just a matter of recognizing that sqrt() has two possible solutions
3. (E) ... we can also plug example values for a and b if the answer is not evident