[sonikamadala]

Originally Posted by sonikamadala

Hi IMo answer is B.

Here is my explanation..

Ploblem is easy if we substitute samll numbers.

consider FS1:
------------
given b2 >a2 => b>a

if b = 2, a=1 then a-b/b+a <1
if b= 2 , a= -3 then a-b/b+a >1

so FS1 alone is not sufficient.


Consider FS2:
-------------
given a — b > 1 => a > 1+b

for any values of a and b, which satisfy this condition the value of
a-b/b+a is >1

Ex : b= -10, a = -8
b = 1, a= 3
b = -10 a= 8 etc

so FS2 alone is sufficient.

So answer is B.

I hope this is clear.

small correction :
for any values of a and b, which satisfy this condition the value of
a-b/b+a is <1 not a-b/b+a is >1. Mistakenly written.