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Here is a different approach ..
To find the Product of all even integers from 2 to n inclusive means finding the product of all integers from 2 to n inclusive that are multiple of 2.
= { ( Last term - First term ) / 2} +1 , so
h(n) = { (n-2) / 2 } + 1 , now we should find p which = h(100)+1
Using the above formula and plugin 100 for n
h(100) = { ( 100-2 ) / 2 } +1
h(100) = (98/2) +1
h(100) = 49 + 1 = 50
Since P= h(100) + 1 then,
p = 50 + 1 = 51 which is greater than 40 .. E is the answer.
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