vaishuhgmail.com Posted June 15, 2006 Share Posted June 15, 2006 can anyone help me in solving the following questions 1. An IV order requires 5 million units of sodium penicillin G to be added to 1 liter of normal saline.How many mEq of sodium r avaible per litre of solution? answer given is 154 2.An order calls for 500ml of a solution of potassium sulfate to be made so that it contains 10 mEq of potassium.How many grams of potassium sulfate r required? answer is 0.870 3. How many millilitres of a 10% KCL(mol. wt 74.6)solution contains 5 mEq of potassium? answer is 3.73 Quote Link to comment Share on other sites More sharing options...
jak073 Posted June 16, 2006 Share Posted June 16, 2006 let me know what u think: can anyone help me in solving the following questions 1. An IV order requires 5 million units of sodium penicillin G to be added to 1 liter of normal saline.How many mEq of sodium r avaible per litre of solution? answer given is 154 is there something value missing from this calculation? 2.An order calls for 500ml of a solution of potassium sulfate to be made so that it contains 10 mEq of potassium.How many grams of potassium sulfate r required? answer is 0.870 MWt of K2SO4 = 174.3 g/mol, there are 2 valence of each ion so 174.3 mg = 1mmol= 2 mEq of K or SO4 so 174.3mg/ 2 mEq = X mg / 10 mEq X = 871.5 mg = 0.8715 g 3. How many millilitres of a 10% KCL(mol. wt 74.6)solution contains 5 mEq of potassium? answer is 3.73 10 % = 10 g/100mL so find the mass of potassium in 5 mEq : 74.6 mg/ 1 mEq = X mg/ 5mEq X = 373 mg = 0.373 g so in 10% there is : 10g/100mL = 0.373 g/ X mL X= 3.7 mL Quote Link to comment Share on other sites More sharing options...
vaishuhgmail.com Posted June 16, 2006 Author Share Posted June 16, 2006 hey jak million thanks to u for the solution. The question is the same as i have posted,dont know what is missing,but a little bit explanation says 9000/58.5=153.8 dont know how it is calculated.:hmm: Quote Link to comment Share on other sites More sharing options...
pharmpi Posted June 16, 2006 Share Posted June 16, 2006 The sodium present in sodium penicillin G must be included in the sodium count. 400,000 units of Penicillin G is = 250mg These might help the problem, but i still can't figure it out. Quote Link to comment Share on other sites More sharing options...
Canpharm Posted June 16, 2006 Share Posted June 16, 2006 Normal Saline is 0.9% NaCl. This is 0.9g/dL or 9g/1000mL = 9000mg Molecular weight of NaCl is 58.5 so 9000mg/58.5mg/mmol = 154mmol Na is monovalent so 154mmol gives 154mEq of Na. They did not add the Na from the penGNa. It gives 2mEq/1million units Quote Link to comment Share on other sites More sharing options...
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