distance and rate

[ska7945]

Al, Pablo, and Marsha shared the driving on a 1,500-mile trip. Which of the three drove the greatest distance on the trip?

(1) Al drove 1 hour longer than Pablo but at an average rate of 5 miles per hour slower than Pablo.

(2) Marsha drove 9 hours and averaged 50 miles per hour.

[pkn_03]

Al(A), Pablo(P), Marsha(M)
Distance(D) = Speed(S)* Time(T)

STEM 1:
TA = TP + 1, A could have driven lesser distance if P was much faster than A, and we know nothing about M
SA = SP - 5, A could have driven significantly more time than P, and we know nothing about M
Hence STEM1 by itself is inconclusive

STEM 2:
TM = 9, SM = 50 --> DM = 450 --> So DA + DP = 1050
Clearly A or P should drive more distance than M, but dodnot know the relation between distances driven by A and P. Hence STEM2 by itself is inadequate.

Combining STEM1 and STEM2

DA = (TP + 1) * (SP - 5) = DP + SP - 5*TP - 5

We donot know if SP - 5*TP - 5 is positive or negative to know, which of DA or DB is greater?

Another possible equation is DA + DP = 1050 --> 2*DP + SP - 5*TP - 5 = 1050. This still doesnot anser the above question.

Hence answer is E.

[gcvbt7t]

My answer is E

[Shooter]

Yes, I agree that we cannot solve for the value. But if we just try random numbers, we are getting Al has traveled the longest distance.

Al: 5m/h lower than pl but 1hr longer

Al: 45m/h ;3hr => 135m
pl: 50m/h;2hr => 100m

Al: 120 m/h; 5hr =>600
Pl: 125 m/h; 4hr =>500

Any thoughts

[ramiy]

E i vote for

[bose]

imo E

[ankitharish]

E it is.2 variables and only one equation.So inconclusive

[sushkan2008]

E ...2 variables and equation...