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Old 2008 October 9th, 04:46 AM   #1 (permalink)
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Wind speed

When the wind speed is 9 miles per hour, the wind-chill factor
w is given by w = -17.366 + 1.19t, where t is the temperature in degrees Fahrenheit. If at noon yesterday the wind speed was 9 miles per hour, was the wind-chill factor greater than 0 ?
(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.
(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit.

OA is
SPOILER: E
, IMO
SPOILER: A

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Old 2008 October 9th, 06:58 AM   #2 (permalink)
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E is correct
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Old 2008 October 9th, 07:13 AM   #3 (permalink)
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w = -17.366 + 1.19t

For my convenience I'll write this as

w = -17+t (rounded off)

For w to be greater than '0', 't' should be at least 18.

(I) t>10 INSUFF
(II) t<20 INSUFF

(I)+(II) still value can be 11 or 18 INSUFF
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Old 2008 October 9th, 11:33 AM   #4 (permalink)
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imo e too
as 1 + 2 gives -6 <w<5
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