try this..good question...

[supersuj]

What is the probability that and are reciprocal fractions?

(1) v, w, y, and z are each randomly chosen from the first 100 positive integers.

(2) The product (u)(x) is the median of 100 consecutive integers.

[e.cartman]

Hmm..Looks like A to me. For random selections from a known range, there must be a way to find the probability.
With stmt 2, we have no information vwyz so imo can't find the probability.

But I think I am missing the point behind this question.

[genius_in_the_gene]

Wrong ans

[supersuj]

What is the probability that (u/v)/w * (x/y)/z = 1 ?

or (ux/vy)/wz =1 ?

ux/vy = wz

or ux = vywz ?

Statement 1-->
we know that the product of vywz is an integer (all 4 are randomly selected from the first 100 integers), but we dont know anything about u and x........INSUFFICIENT

Statement 2-->
Median of 100 consecutive integers is NOT an integer, so we know that ux is not an integer
We know nothing about vywz .......INSUFFICIENT

Combining 1 and 2,

vywz is an integer and ux is NOT an integer, so there is NO WAY
that vywz=ux !....SUFFICIENT

Answer is C

[genius_in_the_gene]

What is the probability that (u/v)/w * (x/y)/z = 1 ?

or (ux/vy)/wz =1 ?

ux/vy = wz

or ux = vywz ?

Statement 1-->
we know that the product of vywz is an integer (all 4 are randomly selected from the first 100 integers), but we dont know anything about u and x........INSUFFICIENT

Statement 2-->
Median of 100 consecutive integers is NOT an integer, so we know that ux is not an integer
We know nothing about vywz .......INSUFFICIENT

Combining 1 and 2,

vywz is an integer and ux is NOT an integer, so there is NO WAY
that vywz=ux !....SUFFICIENT

Answer is C

Good one

[TaTum]

Very interesting question. Agree with supersuj's explanation; the answer should be C, with the zero probability.

What's Official Answer?

[e.cartman]

Yeah, good one about the median being non-integer.