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#11 (permalink) |
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Within my grasp!
![]() ![]() Join Date: Jan 2007
Posts: 409
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Great eye opener... because in such questions top of mind says that since consecutive .. hence divisible by 3.. hence A..
The only prob is .. i ahve seen so many questions on this type on this forum and some other places as well.. that it never occurred in my mind.. certainly useful.. Thanks |
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#13 (permalink) |
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I JUST got here.
![]() Join Date: Oct 2004
Location: Saigon
Posts: 26
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In my opinion, there's a flaw in the Official Explanation. We all know that 0 is divisible by any number, except 0. My answer is A. Here is why.
(1) n2 + n = n(n+1) is not divisible by 3 ==> n = 3m + 1 & n+1 = 3m + 2, where m is an integer. ==> n-1 = 3m is divisible by 3 ==> Sufficient (2) 3n+5 >= k + 8, where k is a positive multiple of 3 ==> n >= k/3 + 1 Given that k is a positive multiple of 3, we know that n must be greater than or equal to 2. We get no further information about n. ==> Insufficient From (1) & (2), answer is A. |
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