cow and computer

[crazy800]

* Of the 60 animals on a certain farm, 2/3 are either pigs or cows. How many of the animals are cows?

(1) The farm has more than twice as many cows as it has pigs
(2) The farm has more than 12 pigs

OA

SPOILER: C

* A store purchased a Brand C computer for the same amount that it paid for a Brand D computer and then sold them both at higher prices. The store's gross profit on the Brand C computer was what percent greater than its gross profit on the Brand D computer?

(1) The price at which the store sold the Brand C computer was 15 percent greater than the price at which the store sold the Brand D computer
(2) The store's gross profit on the Brand D computer was $300

OA

SPOILER: E

[vgp]

???? why C

There are 40 cows and 20 pigs or vice versa.
1) Enough! We know that there are 40 pigs and 20 cows
2) Not useful information.
A

[vgp]

g purchase price G selling price
c purchase price C selling price
c =g=x
We need to find out ((C-x)-(G-x))/C-x=C-G/C-x
C=G+0,15G not enough info.
G-x=300 Not enough info.
1 and 2, not sufficient info.
we need the value of C, G and x to plug in C-G/C-x

[vgp]

OK lets say that “animals” are not just cows and pigs. “2/3 are either pigs or cows” then info can be interpreted as there are either 40 pigs or 40 cows and there are 20 animal mix. In this case the argument that “there are twice as many cows as pigs” still holds! Because we know that 2/3 are either pigs or cows. Pigs cannot be 2/3 or 40 because there are twice as many cows (or 80 which contradicts with the given information)!

[zapped]

@vgp i think you comprehended the question (cows and pigs) wrong.
2/3 of total animals (cows, pigs, etc) =40. so total number of cows and pigs is 40. We need to find out exactly how many cows.
Using A - C>2P, therefore (C,P) can be (30,10); (29,11); (28,12) and (27,13). So we don't know "exact" number yet.
Using B - (C,P) can be (27,13), (26, 14)........(1,39)
Combining we get (C,P)= (27,13) which gives the exact number So IMO C

[nithesh]

zapped is right. i could not understand how is vgp interpreting the question yet!!!

[bizwizashish]

Originally Posted by zapped

@vgp i think you comprehended the question (cows and pigs) wrong.
2/3 of total animals (cows, pigs, etc) =40. so total number of cows and pigs is 40. We need to find out exactly how many cows.
Using A - C>2P, therefore (C,P) can be (30,10); (29,11); (28,12) and (27,13). So we don't know "exact" number yet (oops! i guess question says as many as twice)... i.e if pigs are X then cows are 2x... vgp was correct in calculating this....i guess the issue is we dnt know about rest 1/3.
Using B - (C,P) can be (27,13), (26, 14)........(1,39)
Combining we get (C,P)= (27,13) which gives the exact number So IMO C

See the comments

[bizwizashish]

Originally Posted by bizwizashish

See the comments

Oops ! now seems i din't read the question properly.... u r right zapped.... its more than twice as many


IMO C

[KrazyGMAT]

why is the aswer to the second question not A...............cp is same for both....if am not rong.....so 15% more sp means 15% mre profit.

[genius_in_the_gene]

C= cows
P= pigs

C+P=40

1) C>=2P

If C=2p+1
Then P= 13( the maximum int value of P)
As C becomes more than 2p, P decreases.
But we dont know about the lower limit of P
Not suff
2) p>12

From 1 and 2, the only int >12 and <=13 is 13.

Hence p=13 and C = 27

Hence C