A median question

[Mits83]

Set K consists of 4 integers. What is the median of K ?

(1) The average (arithmetic mean) of K is 3.

(2) The mode of K is 3.

SPOILER: OA: C

[RHYME800]

Originally Posted by Mits83

Set K consists of 4 integers. What is the median of K ?

(1) The average (arithmetic mean) of K is 3.

(2) The mode of K is 3.

SPOILER: OA: C

From Statement 1, we get the total of the 4 integer. (4*3= 12) INSUFFICIENT
From Statement 2, it can be inferred that 3 exists in the set atleast for 2 times. INSUFFICIENT
Taking togather, we can arrange the set as (0 3 3 6)or (1 3 3 5) or (2 3 3 4) or (3 3 3 3) AND NOTHING ELSE. SUFFICIENT TO GET THE VALUE OF K

C is my pick

[finsisher]

This question is badly constructed , I guess only integer is not sufficient you have to mention +ve integer in the question.... also if Mod is 3 doesn't mean that 3 has to be at least twice we might have to see the restrictions..

eg: -3 , 0 ,3,12 is one such group
0,3,4,5 is also one such group..

wots the source of the question?

[Mits83]

Originally Posted by RHYME800

Taking togather, we can arrange the set as (0 3 3 6)or (1 3 3 5) or (2 3 3 4) or (3 3 3 3) AND NOTHING ELSE. SUFFICIENT TO GET THE VALUE OF K

C is my pick

how about (0,1,3,3) or (3,3,7,9).. then the median is not 3..

this is from a free trial of magoosh..

[RHYME800]

Originally Posted by Mits83

how about (0,1,3,3) or (3,3,7,9).. then the median is not 3..

this is from a free trial of magoosh..

NOT possible as the average is 3 in the 4 element set. the total MUST be 12

[Mits83]

oh right.. thanks rhyme

[clock60]

why not C
(1) not sufficient but gives as that sum of 4 integers
x1+x2+x3+x4=12
(2) mod=3 (not sufficient many set are possible)
but together
if mod is 3 it means that at least two integers out of 4 must be 3
please correct me if i am wrong
so possible sets
3,3,3,3 median=3
2,3,3,4 median 3
-3,3,3,9 median 3
0,3,3,6 and so on...
my pick for C

[Brent Hanneson]

Originally Posted by finsisher

This question is badly constructed , I guess only integer is not sufficient you have to mention +ve integer in the question.... also if Mod is 3 doesn't mean that 3 has to be at least twice we might have to see the restrictions..

eg: -3 , 0 ,3,12 is one such group
0,3,4,5 is also one such group..

wots the source of the question?

I'm not sure what you're saying here.

I don't think we need to add the requirement that the numbers must be positive .
I guess it comes down to whether it's correct to say that the mode of {0, 3, 4, 5} is 3. I don't think so. I'd say that {0, 3, 4, 5 } has 4 modes (they are 0, 3, 4, and 5). That said, I might say that 3 is a mode of {0, 3, 4, 5}.
I believe that, for 3 to be the mode of a set of four numbers, we'd need to have 2 or more 3's in the set.

Perhaps the question could read "the one mode of four integers is . . . " but I think might be reduntant since the "the" implies exclusivity. For example, I would say, "which of the following is a solution to the equation x^2 - 9 = 0" (since there is more than 1 solution here). Conversely, I would say, "which of the following is the solution to the equation x+3 = 4" (since there is only one solution here).

[nverma]

Clever question..!!

IMO C.. No doubts..