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#1 (permalink) |
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I JUST got here.
Join Date: Jul 2007
Posts: 2
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12th OG: DS #128
A school administrator will assign each student in a group of n students to one of m classrooms. If 3 < m < 13 < n, is it possible to assign each of the n students to one of the m classrooms so that each classroom has the same number of students assigned to it?
I. It is possible to assign each of 3n students to one of m classrooms so that each classroom has the same number of students assigned to it. II. It is possible to assign each of 13n students to one of m classrooms so that each classroom has the same number of students assigned to it. OA: B <--- Highlight to see the OA iblurker comments Last edited by thatsku : 2009 November 5th at 05:33 AM. Reason: no reason |
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#4 (permalink) |
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Within my grasp!
![]() ![]() Join Date: Jun 2009
Location: mumbai
Posts: 292
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m ..classrooms---4 to 12
n...students>13 is it possible to assign each of the n students to one of the m classrooms so that each classroom has the same number of students assigned to it? Implies is n divisible by m? I. It is possible to assign each of 3n students to one of m classrooms so that each classroom has the same number of students assigned to it 3n is a multiple of m,,... insuff II. It is possible to assign each of 13n students to one of m classrooms so that each classroom has the same number of students assigned to it. 13 n is divisible by m.... implies that n is divisible by m... suff B
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Looking high and Low
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#5 (permalink) |
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Within my grasp!
![]() ![]() Join Date: Oct 2009
Posts: 174
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IMO D..
Let n=14, so 3n=42 and 13n= 182.. Statement 1: Is 42 divisible by m, where m=4,5,6,7,8,910,11,12 yes it is divisible by 6 and 7..SUFF. Statement 2: Is 182 divisible by m, where m=4,5,6,7,8,910,11,12 yes it is divisible by 7..SUFF |
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#6 (permalink) |
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Thinking big..
![]() ![]() Join Date: Mar 2008
Location: London
Posts: 138
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given: 3 < m < 13 < n
I. It is possible to assign each of 3n students to one of m classrooms so that each classroom has the same number of students assigned to it. II. It is possible to assign each of 13n students to one of m classrooms so that each classroom has the same number of students assigned to it. Stmt I: 3n/m is an integrer, is n/m an integer? 3n/m = 3(n/m) m varies from 4 to 12. 3 can divide some values between this range, hence 3(n/m) may reduce to a fraction or an integer and hence we can not be sure if n/m would be a fraction or an integer. Hence insufficient Stmt II: 13n/m is an integrer, is n/m an integer? 13n/m = 13(n/m) and m varies from 4 to 12. since 13 can NEVER divide any value of m, n/m is an integer to make 13(n/m) an integer. Sufficient Hence B |
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