beyondenim Posted February 2, 2011 Share Posted February 2, 2011 Attached File. Thanks Quote Link to comment Share on other sites More sharing options...
gmathintsdotcom Posted February 2, 2011 Share Posted February 2, 2011 I don't think your example works here: sqrt = square root if sqrt(n) is an integer (statement 2) then, sqrt(n) x sqrt(n) = n integer x integer = integer therefore n is an integer if the square root of n is an integer, we are basically told that n is a perfect square. hope this helps. This is Question 169 in the Official Guide GMAT: Data Sufficiency 38 | Khan Academy For Khan Academy, this questions begins at 2:35 This is Question 146 in OG 11th Edition, Quote Link to comment Share on other sites More sharing options...
800 Posted February 8, 2011 Share Posted February 8, 2011 From st 1, n^2 = integer - does not confirm that n is an integer. For example, sqrt(2) is not an integer, BUT (sqrt(2))^2 is integer. SO, 1 is not sufficient. A,D out. From st 2, sqrt(n)= integer. SO, n must be an integer. ENOUGH. B is the answer. Quote Link to comment Share on other sites More sharing options...
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