For me ... an interesting one

[ladyp]

Chan and Mieko drove separate cars along the entire lenght of a certain route. If Chan made the trip in 15 minutes, how many minutes did it take Mieko to make the same trip?

1) Mieko's speed for the trip was 3/4 of Chan's average speed.
2) The route is 14 miles long.

SPOILER:
Official Answer is A because when dealing with a fixed distance a person's average speed is inversely related to the amount time required to make the trip.

I picked C

[slkreddy]

option A
From 1) Let the route distance be x miles ,then chan average speed is x/15(miles/min)
meiko speed is 3/4*x/15 = x/20
Meiko takes 20 minutes to cover the distance

From 2) Route is 14 miles long ..this data is not useful(redundant) to find the speed of Meiko
1) is correct

[terminal_gmat]

Option A, as the distance is fixed and as Mieko's speed for the trip was 3/4 of Chan's speed, Meiko will take 4/3 of the time chan takes.
Let me know if i missed something