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Old 03-11-2003, 02:11 PM   #1 (permalink)
seeker
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For the line with equation y=ax+b, ab!=0, the x-intercept is twice the y-intercept.
The slope of the line 1/2

slope can be positive or negative, right?
intercept can be positive or negative? or, does it just means an "absolute value"?
I think the anwer is: the slope = -1/2
isnt' it?

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Old 03-11-2003, 08:28 PM   #2 (permalink)
Scheel
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Quote:
Originally posted by seeker

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For the line with equation y=ax+b, ab!=0, the x-intercept is twice the y-intercept.
The x-intercept is twice the y-intercept: So they must have the same sign. That is: eighther both are positive or both are negative.
This means that slope is negative, and thereby definitly smaller than 1/2.
And you are right that in this case the slope is -1/2
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Old 03-12-2003, 01:11 AM   #3 (permalink)
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Old 08-22-2005, 07:47 AM   #4 (permalink)
rum
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Please clarify bolded part.


The x-intercept is twice the y-intercept: So they must have the same sign. That is: eighther both are positive or both are negative.
This means that slope is negative, and thereby definitly smaller than 1/2.
And you are right that in this case the slope is -1/2
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Old 08-22-2005, 10:46 PM   #5 (permalink)
bragss2
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Insight:
Pls note that "Slope" in trignometry terms mean tan (thita)= Sin thita/Cos thita = y/x when c=o in the eqn y=mx + c, meaning when the line passes through (0,0)
x intercept is the numeric value of x when y=0 in the line eqn y=mx+c. This is the point where the line cuts the x-axis
Similarly
y intercept is the numeric value of y when x=0 in the line eqn y=mx+c. This is the point where the line cuts the y-axis.
Hope I am making it little clear.
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