its E.
its very obvious frm 2 statement tht they arent sufficient on their own.
Lets combine. M&R both cant be on negative side since 12 divides them. hence either m,r > 0 or say m<0 and r>0
m,r>0
lets distance from 0 tom =x ; so between 0 &r = 3x; combining with statement 2 numberline will look like this
0--------m--------12--------r--
<----x---><---x----><---x--->
solving we get 2x=12, x = 6 m=6 & r =18 satisfies both statement.
but lets m<0 and r>0
m------0-------12------|------r---
<--x---><--x--><---x--><--x-->
so x = 12
thn values of m = -12 and r = 36 also
so we have 2 values of m & R .
C: Insuff
it sud b E



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