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even or not


hitzs

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It's E. Taking both statements together, x could be 1, in which case the answer to the question is no. Or x could be 64, in which case the answer to the question is yes. Two different answers to the question... insufficient. (In fact, any number that is the 6th power of an integer will satisfy both statements. x could be 1^6, 3^6, 5^6, etc. -- all odd. Or x could be 2^6, 4^6, 6^6, etc. -- all even.)
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11. Is x an even integer?

(1) x is the square of an integer.

int = 3, so x=9, and x is not even

int = 2, so x=4, and x is even

(insuff) BCE

 

(2) x is the cube of an integer.

int = 3, so x=27, and x is not even.

int = 2, so x=8, and x is even

(insuff) CE

 

(T) int = 1, so (1) x = int^2 = 1, and (2) x = int^3 = 1, and x is not even

int = 0, so (1) x = int^2 = 0, and (2) x = int^3 = 0, and x is even

 

or follow 800Bob's logic

if x=64, then (1) int=8, and (2) int=4, and x is even

if x=1, then (1) int=1, and (2) int=1, and x is not even

(insuff),

 

Answer E.

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