Jump to content
Urch Forums

x positive w negative


Recommended Posts

  • 2 years later...

Stmt 1:

(pos int)^(neg int)

=1/(pos int)^(pos int)

Compare the denominator with 2. Since (pos int)^(pos int) always results in a pos int, which in this case is 2, how many ways are there to express 2 in that way?

Since sqrt(2), cuberoot(2), etc.. are all non-integers, you can't raise to any pos int higher than 1 like 2,3, etc. So there is unique solution.

If it had been 1/4 on RHS, then you would have got 2 solutions -- 4^-1 and 2^-2.

Link to comment
Share on other sites

Amilli,

I would like to clear your doubt.

x^w = 1/2 = 2^(-1)

This holds good here because we are given that x is +ve and w is -ve integer.

Let us see what other possibilities are:

1/2 = 8^(-1/3) = 512^(-1/9) ... etc.

Here x is +ve but w is a fraction.

Each of these possibilities does not satisfy the given conditon that x is +ve integer and w is a -ve integer. So except for x=2, w=-1 there is no other combination which satisfies this condition.

Hope it clears the doubt. :)

Link to comment
Share on other sites

Thanks guys, I do believed the ans was correct, I just wanted a methodical way to approach this type of problem, I mean it can make sense once you see the ans, but I want to know a reliable way to get there.

 

Cartman,

thanks your explanation is the best way i've seen to look at the problem.

 

thank you too 12rk34

Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...