iknownoone Posted May 9, 2006 Share Posted May 9, 2006 If x is a positive integer and w is a negative integer, what is the value of xw? (1) x^w = 1/2 (2) w = -1 Please provide your explanations. Thanks! Quote Link to comment Share on other sites More sharing options...
manish8109 Posted May 9, 2006 Share Posted May 9, 2006 Ans A Stat 1: x^w = 1/2= 2^(-1) so, x=2 & w=-1 then, xw=2*(-1)=-2-------sufficient Stat 2: w=-1 x^-1=1/x don't know what x is so insufficient Quote Link to comment Share on other sites More sharing options...
safazal Posted May 10, 2006 Share Posted May 10, 2006 The Ans is A. Quote Link to comment Share on other sites More sharing options...
Trouble Posted May 10, 2006 Share Posted May 10, 2006 if w is -ve and x is +ve,from st1==> x^w=i/2==> x=2 and w=-1...x*w=-2==>suff. w=-1 we know nothing about x so St2: insuff. Answer (A) Quote Link to comment Share on other sites More sharing options...
iknownoone Posted May 11, 2006 Author Share Posted May 11, 2006 The OA is A. Quote Link to comment Share on other sites More sharing options...
Amilli Posted October 11, 2008 Share Posted October 11, 2008 Is there a methodical why at arriving at x=2 w=-1, because to me it doesn't seem that intuitive (I know,"what a dumb a**") Quote Link to comment Share on other sites More sharing options...
genius_in_the_gene Posted October 11, 2008 Share Posted October 11, 2008 x^w=1/2=2^-1 Since w x=2, w=-1 Hence A Quote Link to comment Share on other sites More sharing options...
Amilli Posted October 11, 2008 Share Posted October 11, 2008 x^w=1/2=2^-1 Since w x=2, w=-1 Hence A I don't see a method there, you just wrote the ans... same one that had been posted a few times earlier with less explanation. Quote Link to comment Share on other sites More sharing options...
e.cartman Posted October 12, 2008 Share Posted October 12, 2008 Stmt 1: (pos int)^(neg int) =1/(pos int)^(pos int) Compare the denominator with 2. Since (pos int)^(pos int) always results in a pos int, which in this case is 2, how many ways are there to express 2 in that way? Since sqrt(2), cuberoot(2), etc.. are all non-integers, you can't raise to any pos int higher than 1 like 2,3, etc. So there is unique solution. If it had been 1/4 on RHS, then you would have got 2 solutions -- 4^-1 and 2^-2. Quote Link to comment Share on other sites More sharing options...
12rk34 Posted October 12, 2008 Share Posted October 12, 2008 Amilli, I would like to clear your doubt. x^w = 1/2 = 2^(-1) This holds good here because we are given that x is +ve and w is -ve integer. Let us see what other possibilities are: 1/2 = 8^(-1/3) = 512^(-1/9) ... etc. Here x is +ve but w is a fraction. Each of these possibilities does not satisfy the given conditon that x is +ve integer and w is a -ve integer. So except for x=2, w=-1 there is no other combination which satisfies this condition. Hope it clears the doubt. :) Quote Link to comment Share on other sites More sharing options...
Amilli Posted October 12, 2008 Share Posted October 12, 2008 Thanks guys, I do believed the ans was correct, I just wanted a methodical way to approach this type of problem, I mean it can make sense once you see the ans, but I want to know a reliable way to get there. Cartman, thanks your explanation is the best way i've seen to look at the problem. thank you too 12rk34 Quote Link to comment Share on other sites More sharing options...
bose Posted October 15, 2008 Share Posted October 15, 2008 imo a Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.