LinkBack URL
About LinkBacks
Reply With Quotex-y+1 > x+y-1
-y+1 > y-1
2 > 2y
1 > y ?
1) x > 0, not suff
2) y < 0,
Then y < 1 also.
Hence B
|
4. Is x-y+1 greater than x+y-1
(1)x>0
(2)y<0
|
x-y+1 > x+y-1
-y+1 > y-1
2 > 2y
1 > y ?
1) x > 0, not suff
2) y < 0,
Then y < 1 also.
Hence B
.gif "nenuphani's Avatar")
|
Its E.
|
To me its B....as solved by MOM
Lets do it !!!
|
it should be E, as we can also take fractions
for eg if y= - 0.5 then though it is less than zero but greater than 1
& if y= - 2, then its greater than 1 hence no concrete solution
|
Can someone please explain the reasoning behind E? I still end up getting B.
thanks!
It'S bEtTeR tO BuRn oUt ThAn fAdE AwAy!!
|
B is the correct answer
|
Agree with B
|
B is correct.
|
agree with b
There are currently 1 users browsing this thread. (0 members and 1 guests)
Posting Permissions
Bookmarks