adiknish Posted July 14, 2006 Share Posted July 14, 2006 I don' understand how both are sufficient, any thoughts? Thank you in advance for your help! Quote Link to comment Share on other sites More sharing options...
iisan Posted July 14, 2006 Share Posted July 14, 2006 x + y = z ---------------(1) 0.1x + 0.02y = 0.05z ----(2) i. y = 10 ---------(3) 3 eqns, 3 unknowns. Solvable (SUFF) ii. z = 16 ---------(4) 3 eqns, 3 unknowns. Solvable (SUFF) Ans D. Quote Link to comment Share on other sites More sharing options...
arjmen Posted July 14, 2006 Share Posted July 14, 2006 x/y = (5-2)/(10-5) = 3/5 ---> Eq.1 x/z = x/(x+y) = 3/8 ---> Eq.2 I: Suff II: Suff Quote Link to comment Share on other sites More sharing options...
vishalsoft Posted July 14, 2006 Share Posted July 14, 2006 D it is 10 %of x+2%of y=5%of z where Z is x+Y Quote Link to comment Share on other sites More sharing options...
adiknish Posted July 14, 2006 Author Share Posted July 14, 2006 Thank you everyon!! I must be knee deep in material because that was soooo incredibly simple....I just did not see it....how didn't I see that? Quote Link to comment Share on other sites More sharing options...
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