1. Good post? |

## xy plane

aashu help

2. Good post? |
since (-a,b) and (-b,a) are on the same quadrant then tank = (a-b)/(-b+a) = 1 so pts. are on 1st or 3rd quadrant (since tank is +ve)
a) xy > 0 pts. (x,y) are on 1st or 3rd quadrants --insuff--
b) ax > 0 pts. (a,x) are on 1st or 3rd quadrants --insuff--
a), b) if we multiply ax>0 by 1/xy we have a/y>0 or ay > 0
so we get followimg cases
i)a > 0, y > 0, -x < 0 so (-x,y) -->(2nd quadrant)
ii)a < 0, y < 0, -x > 0 so (-x,y) -->(4th quadrant)
so (-x,y) is not in the same quadrant with other 2 pts.
--c--

3. Good post? |
The quadrant is determined by the sign of x & y coordinates.
(+,+) - 1st
(-,+) - 2nd
(-,-) - 3rd
(+,-) - 4th

Now question -

(-a, b) & (-b, a) are in same quadrant
=> a and b have same sign,(either both are +ve or -ve)

(-x, y) will be in the same quardant if
both x y have same sign and also sign of x & y is same as that of a & b

1> tells x,y are of same sign but not sure if its same as that of a & b
2> tells a,x (and b) are of same sign but we don't know sign of y

combining => a,b,x,y are of same sign hence (-a,b), (-b,a), (-x, y) will be in the same quadrant.
infact (-a,x) (-b,x) (-a,y) (-b,y) will also be in the same quadrant.

This is sufficient. (even though we don't know which quadrant they will be in, may be in either 1st or 3rd quadrant depending on the sign)

4. Good post? |
Originally Posted by aashu_79
1> tells x,y are of same sign but not sure if its same as that of a & b
if x y are od same sign then both are either + or -.
since a and b are either + or - which is in 1st or 3rd quadrant,
x and y are also in either 1st or 3rd quadrant.

so i concluded that this is Suff.

thats what i was thinking but not sure whats wrong with my logic.

any more insight Aashu?

5. Good post? |
Originally Posted by MikeJung
if x y are od same sign then both are either + or -.
since a and b are either + or - which is in 1st or 3rd quadrant,
x and y are also in either 1st or 3rd quadrant.

so i concluded that this is Suff.

thats what i was thinking but not sure whats wrong with my logic.

any more insight Aashu?
This condition will not be called sufficient.
Sign of x & y is independent of sign of a & b. Lets say we know that a & b are +ve . Can we say anything about x&y? No. x & y may still be +ve or -ve.
No clear answer means insufficient condition.

6. Good post? |
^ great

u my hero Aashu!

There are currently 1 users browsing this thread. (0 members and 1 guests)

#### Posting Permissions

• You may not post new threads
• You may not post replies
• You may not post attachments
• You may not edit your posts
•

SEO by vBSEO ©2010, Crawlability, Inc.