spoud74 Posted February 23, 2007 Share Posted February 23, 2007 There is a park in a parallelogram shape. Person A walks along the longer diagonal. Person B walks along the shorter one. Does A cover 1.5 times the distance B covers? 1. Parallelogram has one side 1 km and another side 2km 2. One of the internal angles of the parallelogram is 60 degrees Question is essentially asking if one diagonal is 1.5 times the other diagonal. Quote Link to comment Share on other sites More sharing options...
prepfortests Posted February 23, 2007 Share Posted February 23, 2007 You need both the lengths of the sides AND the angles to work out the ratio between the two diagonals of a parallelogram so the answer is C. Quote Link to comment Share on other sites More sharing options...
prasdude Posted June 13, 2008 Share Posted June 13, 2008 Have a doubt regarding the second condition: We know that the relative size of side corresponds to the angle opposite it. i.e. The greater the angle the greater the side opposite it. In this problem we know that one angle is 60 and the other is 120. i.e double the other. As the sides subtending these angles is the same(1 and 2 in this case), can we relate that the side opposite 120 is double that opposite 60? Quote Link to comment Share on other sites More sharing options...
rockysethi Posted June 14, 2008 Share Posted June 14, 2008 prepfortests..can u plz explain ur answer.. Quote Link to comment Share on other sites More sharing options...
saege Posted June 14, 2008 Share Posted June 14, 2008 Spoud74 can you post the OA please Tks Quote Link to comment Share on other sites More sharing options...
Makumajon Posted June 15, 2008 Share Posted June 15, 2008 (1) Inufficient. The diagonals will be such that 1 (2) Angles are known, but not the sides. Combining: sufficient, since for given angles & sides, the diagonals are fixed, whatever their values are. C Quote Link to comment Share on other sites More sharing options...
gmatcraze Posted August 14, 2008 Share Posted August 14, 2008 (1) Inufficient. The diagonals will be such that 1 (2) Angles are known, but not the sides. Combining: sufficient, since for given angles & sides, the diagonals are fixed, whatever their values are. C Makumajon, how do you know that the diagonal is 1 Secondly, how can knowing the angles and the sides help in solving this. Assuming this to be a PS question, can you show how to solve. Thanks Quote Link to comment Share on other sites More sharing options...
Makumajon Posted August 14, 2008 Share Posted August 14, 2008 Simply apply the parallelogram theorem of vector addition. If you are not aware of this theorem, which might be the case if you are not a science student, please let me know. I would try another way. Quote Link to comment Share on other sites More sharing options...
gmatcraze Posted August 14, 2008 Share Posted August 14, 2008 Simply apply the parallelogram theorem of vector addition. If you are not aware of this theorem, which might be the case if you are not a science student, please let me know. I would try another way. Sorry, I do not know this theorem ... please help to solve in some other way ... Thanks Quote Link to comment Share on other sites More sharing options...
Queen09 Posted August 15, 2008 Share Posted August 15, 2008 clue is For any triangle with sides a, b , c a+c > b >|a-c| Quote Link to comment Share on other sites More sharing options...
Test Taker Posted August 18, 2008 Share Posted August 18, 2008 Are the diagonals of a parallelogram angular bisectors? Quote Link to comment Share on other sites More sharing options...
Makumajon Posted August 18, 2008 Share Posted August 18, 2008 True for a square and rhombus, not for typical parallelogram or rectangle. First draw a parallelogram. Then extend the larger side keeping other things constant; you would see that the larger diagonal is moving to the larger side, becoming closer to it, thus reducing one angle but increasing the other angle. Quote Link to comment Share on other sites More sharing options...
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