anyone please let me know the stategy to solve this problem. :)

[mauni]

.* If y≠0 and y≠-1, which is greater,
x/y or x/(y+1)

(1) x≠0
(2) x > y
OA

SPOILER: e

[lsr]

Originally Posted by mauni

.* If y≠0 and y≠-1, which is greater,
x/y or x/(y+1)

(1) x≠0
(2) x > y
OA

SPOILER: e

Question stem:
Is x/y > x/(y+1) ?

If x = 0, the two sides are equal.

Otherwise, there are three cases to consider:
1)For y>0; is x>0 ?
2)For y<-1; is x>0 ?
3)For -1<y<0; is x<0 ?

First statement:
x does not equal zero; we know that the two are not equal, but that's all.
Not sufficient.

Second statement:
x>y; x and y can both be negative or positive, or y is negative and x is zero or positive.
Not sufficient.

Both statements:
Not sufficient.

Answer is E.

[mauni]

thank you

[CrackXam]

Agreed with lsr. E it is.

you can try taking example of integers and fractions to check the cases mentioned by lsr. (Examples make my life easier)!

[anujgoyal11]

Very well explain.. Thanks

Another vote for E

[qwertzy]

Let A = x/y
Let B = x/y+1

I draw out a matrix for this question:

for x<y:

+ve y: A > B
-ve y: A < B

for x>y:
+ve y: A <B
-ve y: A>B

Statement 1 doesn't help at all.
Statement 2 only rules out x<y, still leaving 2 more case.
Insufficient.
Hence E.

[qwertzy]

hi guys,
I would like to modify the question to :

(1) x=0 <<<<<<<change to x =0
(2) x > y



How would your answer be different?