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#1 (permalink) |
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Within my grasp!
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Set 25 # 5
If x^3y^4=5,000, is y=5? (2)x is an integer.(1)y is a positive integer. SPOILER: answer C 5000 = 5^ 4 & 2^3. I had answered E since if X is negative then the answer will be negative. hence B does not rule out this possibility. Please help me understand the OA
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#2 (permalink) |
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Within my grasp!
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You have already answered your own question.
x cannot be (-)ve because if x is negetive, then x^3 becomes (-)ve , making the whole expression x^3*y^4 = (-)ve . Why? y^4 is always (+)ve irrespective of y= -ve or +ve So, in order to stand the equation x^3*y^4 = 5000 , x has to be (+)ve. And as per (2) x=integer Hence, both (1) and (2) require to answer this question. I hope that helps. |
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#3 (permalink) |
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TestMagic Guru-in-Training
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You're not differentiating between the statement and the question. "If x^3y^4=5,000" is a statement of a fact. x cannot be negative because we know y^4 is always positive and their product must always be positive.
You can now most likely figure out why individual statements are insufficient and why both combined are sufficient. |
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#4 (permalink) |
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Within my grasp!
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B says X is an integer. hence it can be positive or negative. it does not rule out the possibility of it being negative.
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it is under fire and pressure DIAMONDS are created |
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#6 (permalink) |
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Within my grasp!
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DWarrior
by your logic then the answer will D. If the question is a statement of fact then X & Y will be integer by virtue of A & B individually. 1.e. if A then X automatically will be an integer hence need not to be proven separatly 2. Similarly for B
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it is under fire and pressure DIAMONDS are created |
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