Q3)
St I) The heaviest box on shelf J weighs 15 pounds.
............15............
It is A.Median is 15 as it is the 45 th box and the 44 boxes before it are all lesser than 15 and 44 after it are greater than 15
St II) Gives info only on 46 th Box
Q3:
Each of the 45 boxes on shelf J weighs less than each of the 44 boxes on shelf K. What is
the median weight of the 89 boxes on these shelves?
(1) The heaviest box on shelf J weighs 15 pounds.
(2) The lightest box on shelf K weighs 20 pounds.
-------------------------------------
Q15:
If n and k are positive integers, is n/k an even integer?
(1) n is divisible by 8.
(2) k is divisible by 4.
If x and y are integers and x > 0, is y > 0?
(1) 7x – 2y > 0
(2) -y < x
-------------------------------------
Q35:
In June 1989, what was the ratio of the number of sales transactions made by Salesperson
X to the number of sales transactions made by Salesperson Y?
(1) In June 1989, Salesperson X made 50 percent more sales transactions than
Salesperson Y did in May 1989.
(2) In June 1989, Salesperson Y made 25 percent more sales transactions than in
May 1989.
------------------------
Can some one help me with these problems..
Q15:
If n and k are positive integers, is n/k an even integer?
(1) n is divisible by 8.
(2) k is divisible by 4.
St I) n is divisible by 8, implies n is a multiple of 8.
But we do not know anything abt k. Eg : 8/4 = 2 24/8 =3 . INSUFF
St II) k is divisible by 4 , implies k is a multiple of 4. again no info abt n.INSUFF
From I and II ,
if n= 16 , k=4 then n/k =4
but if n=40, k=8 then 40/8 =5
Hence E
Q35:
In June 1989, what was the ratio of the number of sales transactions made by Salesperson X to the number of sales transactions made by Salesperson Y?
(1) In June 1989, Salesperson X made 50 percent more sales transactions than Salesperson Y did in May 1989.
(2) In June 1989, Salesperson Y made 25 percent more sales transactions than in May 1989.
St I )
Xjune = 1.5Ymay. No Use as we need to find Xjune/Yjune
St II)
Yjune= 1.25Ymay . no help
from I and II
Y may = yjune/1.25
hence Xjune=1.5 ( Yjune/1.25)
Hence C
Answer for 3)A 35)c and 15)c
35 and 15 are ok.
Can you please explain the (3) question,I get the point that 45 position in 15 ,how can you conclude it to be the median ?
Can you please explain this inquality problem..
If x and y are integers and x > 0, is y > 0?
(1) 7x – 2y > 0
(2) -y < x
If x and y are integers and x > 0, is y > 0?
(1) 7x – 2y > 0
(2) -y < x
St I ) 7x – 2y > 0, implies 7x >2y
Moreover x is +ve. so 7x is +ve. 2y can be +ve or -ve. INSUFF
St II) -y < x
y>-x. . But x is +ve. Hence -x is -ve. y can be -ve or +ve again .INSUFF.
From I and II
Let x=2 , then y can be -1, 2
7(2) – 2 (-1) = 14+2 =16
7(2) -2(2) =14 -4 =10
Hence E.
Pls check answer for Q15, it must be E not C
This is very tricky and I learnt it from my mistake.
St I) Heaviest box in J is 15 . This means all other boxes in J are lesser than 15. Question also says All boxes in J are lesser than K. This means least box in K > 15.
So it looks like (for eg).........12,13,15,16............
45 th box is in the middle number as there are 89 boxes. 45 th box also happens to be the heaviest of J. Hence it is the median
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