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#1 (permalink) |
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I JUST got here.
Join Date: Jul 2009
Posts: 7
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The temperature of a certain cup of coffee 10 minutes after it was poured was 120 degrees Fahrenheit. If the temperature F of the coffee t minutes after it was poured can be determined by the formula F = 120 (2^-at) +60, where F is in degrees Fahrenheit and a is a constant, then the temperature of the coffee 30minutes after it was poured was how many degrees Fahrenheit?
a) 65 b) 75 c) 80 d) 85 e) 90 |
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#2 (permalink) |
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Eager!
Join Date: Jun 2009
Posts: 58
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F = 120. 2-at +60
We know that when t = 10 (min.), F = 120 Use this to determine a 120 = 120. 2-a.10 +60 60 = 120. 2-a.10 1/2 = 2-a.10 We know 1/2 = 2-1, so 2-a.10 = 2-1 -a.10 = -1 a= 1/10 -- Now substite t=30 minutes and a=1/10 in the original equation: F = 120. 2-(1/10).30 +60 F = 120. 2-3 +60 2-3 = 1/ (23) = 1/ (2.2.2) = 1/8 F = 120. 1/8 +60 F = 120/8 +60 F = 15 + 60 F = 75 -- -- -- PS It'd be better to post such questions in the 'Problem Solving' section. You'll probably get a quicker response! |
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#3 (permalink) | |
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One last time...!
![]() ![]() Join Date: Jun 2009
Location: Chandigarh
Posts: 453
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