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#1 (permalink) |
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Eager!
Join Date: May 2005
Posts: 67
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Is lx-4l < 7?
(1) X < 3 (2) X > -11 Some say it's' D. Others say it's C. Could someone please put in his/her idea on this matter? I think it's D because in both (1) and (2), we can always make sure of the validity of the given inequality (lX-4l < 7). Please help. |
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#2 (permalink) |
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TestMagic Guru-in-Training
![]() ![]() ![]() Join Date: May 2009
Posts: 728
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i think the answer is E
that is my view /x-4/<7 can be solved as -7<x-4<7. -7+4<x<7+4. so -3<x<11 so the question asks does x belong to the interval (-3, 11) (1) x<3 but what about -5 for example it is less than 3 but doest fit ours insufficient (2) x>-11 insufficient for the same reasoning again -5 it is larger than -11 but does not fit condition (1)+(2) together according we have interval (-11.3) if we put 0 for example the answer is yes but for -5 the answer is no so to my mind E ________ -11_______ -3__________3________11 our interval is (-3 11) any number in (-3 3) will be valid and in (-11 -3) will be invalid. |
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#3 (permalink) |
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Eager!
Join Date: May 2005
Posts: 67
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Sorry, there was a typo. This is the correct problem.
Is lx+4l < 7? (1) X < 3 (2) X > -11 And clock60, you were right on your solution earlier. And using the same logic that you pointed out (when the term inside the abs value sign was x-y), the answer to the above corrected version is C |
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#4 (permalink) | |
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GMAT cracker
![]() ![]() Join Date: Jul 2009
Posts: 221
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Quote:
IMO answer is C (1) : say x = 2 then lx+4l < 7 , if x = -12 then lx+4l > 7. so not suff. (2) : say x = 2 then lx+4l < 7 , if x = 22 then lx+4l > 7. so not suff. (1) & (2) : -11< x< 3 . say x = 2 then lx+4l < 7 , if x = -10 then lx+4l < 7. so suff. so C wins Last edited by sonikamadala : 2009 August 12th at 06:03 AM. |
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