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Old 2009 August 11th, 04:21 AM   #1 (permalink)
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quant -2

1. A person walks for two days. On the 2nd day he walks 2 hrs long and at 1mile per hr more than on 1st day. If he walk for total time of 18hrs & 64 miles over the 2days what was his speed on the 1st day?



2. In 1985 45% of document storage facility's 60 customers were banks and in 1987, 25% of document storage facility's 144 customers were banks. Find the % increase from 1985 to 1987 in the no:of bank customers?
(a)10.7%
(b)20%
(c)25%
(d)100/3 %
(e)175/3 %


as per my solution answer shud be 10.7%.

Thanks
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Old 2009 August 11th, 08:10 AM   #2 (permalink)
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q1
let it be following symbols
t1-the time spent in the first day
t2-the time spent in the second day and t2=t1+2
according to the problem total time is 18 so simply solve equation
t1+t2=18 t1+t1+2=18 so t1=8 and t2=10
v1 is speed on the first day
v2 is speed on the second day and v2=v1+1
total distance =64
t1*v1+t2*v2=64
8*v1+10*(v1+1)=64
18v1=54
v1=3
so the answer is 3
what is oa?
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Old 2009 August 11th, 12:31 PM   #3 (permalink)
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Thanks.. this was a question in a test.. come to think of it.. I did the same thing but went wrng in the basic computation..yeah thats the answer..

what do u think bout the 2nd question?

Thanks
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Old 2009 August 11th, 12:42 PM   #4 (permalink)
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2.answer is 100/3
In the year 1985,45/100*60 = 27
In the year 1987, 25/100*144 = 36
%increase from 1985-1987 is, 36-27/27*100 = 100/3
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Old 2009 August 11th, 01:54 PM   #5 (permalink)
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Quote:
Originally Posted by wanderwanderer View Post
1. A person walks for two days. On the 2nd day he walks 2 hrs long and at 1mile per hr more than on 1st day. If he walk for total time of 18hrs & 64 miles over the 2days what was his speed on the 1st day?



2. In 1985 45% of document storage facility's 60 customers were banks and in 1987, 25% of document storage facility's 144 customers were banks. Find the % increase from 1985 to 1987 in the no:of bank customers?
(a)10.7%
(b)20%
(c)25%
(d)100/3 %
(e)175/3 %


as per my solution answer shud be 10.7%.

Thanks
as for question 2 i am slightly confused with wording
but i do not see the way other than direct
0,45*60=27
0,25*144=36
36-27=9/27*100=33% that corresponds with d
may be i am wrong
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Old 2009 August 12th, 05:23 AM   #6 (permalink)
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This is honestly confusing and also there is change in the strength of teh customers.

so diff in 45% of 60 & 25% of 144 divided by 144-60


so 10.7%.. somehow we being asked to solve a simple prob is hard to digest.
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Old 2009 August 12th, 10:30 AM   #7 (permalink)
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IMO answer is 3 for (1) and 100/3 for (2).

(2) : 40% of 60 = 27
and 25% of 144 = 36

so %age increase = ((36-27)/27) *100 = 100/3
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Old 2009 August 18th, 05:50 AM   #8 (permalink)
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Quote:
Originally Posted by clock60 View Post
q1
let it be following symbols
t1-the time spent in the first day
t2-the time spent in the second day and t2=t1+2
according to the problem total time is 18 so simply solve equation
t1+t2=18 t1+t1+2=18 so t1=8 and t2=10
v1 is speed on the first day
v2 is speed on the second day and v2=v1+1
total distance =64
t1*v1+t2*v2=64
8*v1+10*(v1+1)=64
18v1=54
v1=3
so the answer is 3
what is oa?
Another good explanation Clock60
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