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#1 (permalink) |
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I JUST got here.
Join Date: Aug 2009
Posts: 4
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investment problem
A portion of $6600 is invested at a 5% annual return, while the remainder is invested at a 3% annual return. If the annual income from the portion earning a 5% return is twice that of the other portion, what is the total income from the two investments after one year?
A. 300 B. 180 C. 360 D. 270 E. 320 |
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#2 (permalink) | |
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TestMagic Guru-in-Training
![]() ![]() ![]() Join Date: May 2009
Posts: 726
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Quote:
6600-x was invested at 3% 0,05x=2*0,03(6600-x) according with the condition of the problem now solve the equation and x=3600 3600*0,05=180 (6600-3600)*0,03=90 180+90=270 so answer is D what is oa ![]() |
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