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Old 2009 August 12th, 09:52 PM   #1 (permalink)
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investment problem

A portion of $6600 is invested at a 5% annual return, while the remainder is invested at a 3% annual return. If the annual income from the portion earning a 5% return is twice that of the other portion, what is the total income from the two investments after one year?


A. 300
B. 180
C. 360
D. 270
E. 320
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Old 2009 August 12th, 11:28 PM   #2 (permalink)
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Quote:
Originally Posted by sawhai View Post
A portion of $6600 is invested at a 5% annual return, while the remainder is invested at a 3% annual return. If the annual income from the portion earning a 5% return is twice that of the other portion, what is the total income from the two investments after one year?


A. 300
B. 180
C. 360
D. 270
E. 320
imagine that x was invested at 5% than
6600-x was invested at 3%
0,05x=2*0,03(6600-x) according with the condition of the problem
now solve the equation and x=3600
3600*0,05=180
(6600-3600)*0,03=90
180+90=270
so answer is D
what is oa
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Old 2009 August 13th, 06:39 AM   #3 (permalink)
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Thanx clock,

I don't know the OA
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Old 2009 August 18th, 06:11 AM   #4 (permalink)
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Thanks Clock
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