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#1 (permalink) |
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I JUST got here.
Join Date: Sep 2008
Posts: 9
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Confused on Combinatorics Strategy
Below are 2 combinatoric problems. Both use the same strategy except for the last step, why do I use addition on one of these problems and multiplication on the other?
The 1st problem: A second grade class is writing reports on birds. The students' teacher has given them a list of 6 birds they can choose to write about. If lizzie wants to write a report that includes two or three ofo the birds, how many different reports can she write? 6! = 15 4!2! 6! = 20 3!3! 15 + 20= 35 WHY DO WE USE ADDITION IN THIS CASE AND IN THE BELOW CASE...... The 2nd problem The I Eta Pi fraternity must choose a delegation of three senior members and two junior members for an annual interfraternity conference. If I Eta Pi has 12 senior members and 11 junior members, how many different delegations are possible? 12! = 220 9!3! 11! = 55 9!2! 220 * 55 = 12,100....HOW COME IN THIS CASE WE MULTIPLY??? All help is appreciated. |
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#2 (permalink) | |
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Quant-Master
![]() ![]() Join Date: May 2009
Posts: 167
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Quote:
If the operation to be performed is x or y than we add. In question 1 either 2 or 3 birds. Hence add both the operations. If the operation to be performed is x and y than multiply. In the 2nd question select 3 out of 12 senior members and 2 out of 11 junior members. Here we find number of ways of selecting senior members and number of ways of selecting junior members and we multiply them Thanks, Quant-Master
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