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#1 (permalink) |
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Eager!
Join Date: May 2005
Posts: 67
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I'm editing this post because I checked with a friend who confirmed that the given OA was indeed wrong (original OA was E).
Now that we know that the OA is wrong, the obvious answer here is the correct answer. Hence this should be an easy problem. Sorry all to bother you with this. A and B drive separately to a meeting. A's average driving speed is 1/3 greater than B's, and A drives twice as many miles as B. What is the ratio of the number of hours A spends driving to the meeting to the number of hours B spends driving to the meeting? A.8:3 B.3:2 C.4:3 D.2:3 E.3:8 Last edited by bretania : 2009 August 17th at 03:59 AM. Reason: Found the |
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#2 (permalink) | |
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TestMagic Guru-in-Training
![]() ![]() ![]() Join Date: May 2009
Posts: 728
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Quote:
speed A-4/3x dist B-D dist A-2D time A - (2D)/(4/3)*x time B - D/x time A/ time B=3/2 so B ![]() |
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#4 (permalink) |
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Eager!
Join Date: May 2005
Posts: 67
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Dr GMAT, did you find out the explanation to this already? Just in case, here's my take.
We are asked to compare Ta/Tb (ratio of time for a to the time for b). So first look for Ta and Tb. Because the conditions in A are given as a proportion of the conditions in B, it's better to tackle B first. So, let d be the distance that it will take B to cover the trip. So the distance for a will be 2d. Also, since A's speed is 1/3 more of B's, we can have speed of B as 3s and speed of A as 4s Tb would then be (distance/speed) = d/3s Ta would be =2d/4s Now, Ta/Tb would give us 3/2. Hope this helps. |
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